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6h^2-31h+30=0
a = 6; b = -31; c = +30;
Δ = b2-4ac
Δ = -312-4·6·30
Δ = 241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-31)-\sqrt{241}}{2*6}=\frac{31-\sqrt{241}}{12} $$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-31)+\sqrt{241}}{2*6}=\frac{31+\sqrt{241}}{12} $
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